Balance the following equations. (Use the lowest possible
whole-number coefficients. These may be zero.)
(a) MnO4-(aq) + Cl-(aq) Mn2+(aq) + Cl2(aq)
MnO4- + Cl-
+ H+ + H2O Mn2+
+ Cl2 + H+
+ H2O
(b) Cr2O72-(aq) +
NO2-(aq) Cr3+(aq) +
NO3-(aq)
Cr2O72-
+ NO2- + H+
+ H2O Cr3+
+ NO3- + H+
+ H2O
(c) Tl2O3(s) + NH2OH(aq) TlOH(s) + N2(g)
Tl2O3 + NH2OH
+ OH- + H2O TlOH(s) + N2
+ OH- + H2O
(d) CrO42-(aq) +
C2O42-(aq) Cr(OH)3(s) +
CO2(g)
CrO42-
+ C2O42-
+ OH- + H2O Cr(OH)3
+ CO2 + OH-
+ H2O
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) MnO4-(aq)...
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Cr202-(aq) + NO2 (aq) = Cr3+ (aq) + NO3"(aq) Cr20,2- + NO3 + H+ + H2O= Cr3+ + NO3 + H+ + H20 (b) Mn04 (aq) + CH3OH(aq) Æ Mn2+ (aq) + HCO2H(aq) MnO4 + CH3OH + H+ + H2O= Mn2+ + HCO2H + H+ + H2O (c) ClO2(aq) + H2O2(aq) = C102 (aq) + O2(9) C102 + H2O2 + OH + H20 = ClO2...
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Cr2022(aq) + I (aq) = Cr3+ (aq) + 103 (aq) 1 Cr2O72- + 1 1 + 8 H+ + 1 X H20 = 2 Cr3+ + 1 103 + 1 X H+ + 4 H2O (b) CIO3-aq) + As(s) Æ HCIO(aq) + H3A5O3(aq) 3 CIO3 + 4 As + 3 H...
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) NO3- (aq) + As2O3(s) = N2O3(aq) + H3ASO4(aq) N03* + As2O3 + H+ + O H20=O N203+ H3A504 + H+ + H20 (b) Clozaq) + As(s) Æ HClO(aq) + H3AsO3(aq) DC103+ As + OH+ + H2O=OHCO + H2A503 + H+ + OH20 (c) CIO-(aq) + Pb(OH)42-(aq) = Cl(aq) + PbO2(s) D clo + Pb(OH)42- + D OH + H2O=D C + PbO2 + OH +...
31. + -10.1 points 0/4 Submissions Used Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) CIO (aq) + 12() = Cl(aq) + 103 (aq) CIO + 12+ H H20 = + 103 + H+ H2O (b) NO3 (aq) + As2O3(s) = N2O3(aq) + H3ASO4(aq) NO3 + As2O3 + H+ + H20 = N203 + C H3A504 + H+ + H2O (c) Cro42-(aq) + N2H4(aq) = Cr(OH)3(s) + N2(9) croq²+ NaH4+ OH + H20...
Balance these chemical equations. (Use the lowest possible whole number coefficients.) (a) C4H10 + O2 → CO2 + H2O (b) Pb(NO3)2 → PbO + NO2 + O2 (c) N2H4 + O2 → H2O2 + N2 (d) NH3 + O2 → NO2 + H2O (e) NH3 + O2 → N2 + H2O (f) Fe(OH)2 + O2 + H2O → Fe(OH)3
Balance the following equations. (Use the lowest possible whole number coefficients. Include states-of (2) AIHz(8) + H2O(l) + Al(OH)3(8) + Hz(9) (6) Nb(NO3)(s) Nb2O3(s) + NO2(g) + 02 (9) (C) CH3NH2(g) + O2(g) + CO2(g) + H2O(l) + N2 (9) Submit Answer Try Another Version 10 item attempts remaining
Balance the following redox equations by the half-reaction method: (a) Mn2+ + H2O2 → MnO2 + H2O (in basic solution) (b) Bi(OH)3 + SnO22− → SnO32− + Bi (in basic solution) (c) Cr2O72− + C2O42− → Cr3+ + CO2 (in acidic solution) (d) ClO3− + Cl− → Cl2 + ClO2 (in acidic solution) (e) Mn2+ + BiO3− → Bi3+ + MnO4− (in acidic solution)
References] Balance each of the following oxidation-reduction reactions by using the oxidation states method. (Use the lowest possible coefficients for all reactions.) Cl2(g)+Ga(s)- Ga3 (aq) CI (aq) a. Ga3 (aq)+ CI (aq) Cl2(9) + Ga(s) O2(9)+ H2O(1)+Sn(s)Sn(OH)2(s) b. H2O (1) + O2(9) + Sn(OH)2 (s) Sn(s) H* (aq)MnO4(aq) +Cr2 (aq ) -Mn2 (aq) +Cr3+ (aq) +H2O(l) с. Cr (aq) H (aq) + MnO4 (aq) + Cr (aq) + Mn2+ (aq) + Н. О(1) 6 item attempts remaining Submit Answer Try...
Balance the redox reactions: basic: ClO-(aq)+Cr(OH)4-(aq)----> CrO42-(aq)+Cl-(aq) MnO4-(aq)+Br-(aq)--> MnO2(s)+BrO3-(aq) NO2-(aq)+Al(s)--->NH3(g)+AlO2- Aidic: ClO4-(aq)+Cr(OH)4---->ClO3-(aq)+Cl2(g)
Balance the following equations. (Use the lowest possible whole number coefficients. Include states of matter under the given conditie (a) Cas(PO )2(aq) + H,PO, (aq) + Ca(H,PO)2(aq) chemPad Help X. Xº - Greek (b) ICI,(s) + H2O(g) + 1r02(s) + HCl(g) chemPad Help X.X" e Creek (c) Fe(s) + H2001) -- 70,0 (5) + H2(g) chemPad Help Greek -