Question

Sec7.1: Problem 8 Previous Problem List Next (1 point) Book Problem 21 0 to 3 sin() and y = 4 cos(x) from Sketch the region that lies between the curves y 0.9. Notice that this region consists of two separate parts. Using a graphing calculator, the x-coordinate c of the point of intersection is approximately equal to 927 dx+ Se 0,9 dr The area A of this region is Jc After integrating, A = Note: You an earn partial credit on this problem. Preview My Answers Submit Answers

Answer 1

let f(x)=3sin x and g(x)=4cosx.

Area enclosed between curves y=g(x) and y=f(x) in an interval [a,b] in which f(x)≥g(x) is given by

This is key formula for calculating area.

(f(x) g(x))da

please find image .
=83102x-Fce) 2 2. C=09

point ot irtersectio n C=0.927 1s C. Area SE O9 IT x)-g()dx + C clearty Co,]. can we In interval pul and g ce) fx G-9TT 0.927 A Gsinx-s)d -3810x)drt 11 O-927

idegraling On a. 927 sin xt 3 cos a -4-3999 22 O 3 TT -J. b: -4sin O. 927 +6.517- A = 2 A =8.617 !!