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region between the poles of a large electromagnet. In this region there is a horizontal magnetic field toward the northeast with magnitude 1.20 T. 6 (a) A straight horizontal copper rod carries a current of 50 A from west to east in a i. Sketch the diagram of copper rod in the magnetic field. ii. Find the magnitude and direction of the force on a 1.00 m section of rod ii. While keeping the rod horizontal, how should it be oriented to maximize the magnitude of force? What is the magnitude of force in this case? [10 marks] An electron moves following a circular path in vacuum influenced by magnetic field. The radius of the electron's path is 2.0 x 102 m, magnetic field strength is 2.0 x 102 T, and specific charge electron e/m is -1.76 x 10 Ckg (b) i. Write an expression for angular velocity of electron. ii. Calculate its orbital period. ili What happen to the electron's path when its velocity decreases? [10 marks]

Answer 1

Force acting on conductor is given by F = BI l sin theta B = 1.20 T, I = 50 A l = 1 m theta = 90 degree F = 1.20 times 50 times 1 times sin 90 degree F = 60 N iii the rod should be oriented horizontal (as perpendicular to the B) because the value of sin theta will goes decreasing with change in theta (orientation)