A)
Frequency, f = (1/2π) sqrt(k/m) = (1/2π) sqrt(1.7 x 10^4)/94)
f = 2.14 Hz
B)
Using law of conservation of energy,
0.5 x 1.7 x 10^4 x X^2 = 94 x 9.8 x (2.8 + X)
8500 x^2 - 921.2 x - 2579.36 = 0
X = 0.6077 m = 60.77 cm
C)
Frequency, f = (1/2π) sqrt(k/m) = (1/2π) sqrt(2 x 1.7 x 10^4)/94)
f = 3.03 Hz
D)
Using law of conservation of energy,
0.5 x 2 x 1.7 x 10^4 x X^2 = 94 x 9.8 x (2.8 + X)
17000 x^2 - 921.2 x - 2579.36 = 0
X = 0.4176 m = 41.76 cm
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a-d 1:39:00 PM (9%) Problem 11: The length of nylon rope from which a mountain climber...
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