A pure titanium cube has an edge length of 2.66 in. How many titanium atoms does it contain? Titanium has a density of 4.50g/cm^3.
A pure Titanium cube has edge length = 2.66 inches
density = 4.50 g/cm3
All sides of cube will have length = 2.66 inches
Then volume of length = 2.66 in x 2.66 in x 2.66 in = 18.8210 inches3
1 inch = 2.54 cm
So 1 inch3 = 2.543 cm3 = 16.39 cm3
Then
Volume = 18.8210 inches3 x 16.39cm3 / inch3
= 308.42 cm3
Now we can convert to mass by using density as both are having same units now
308.42 cm3 x 4.5 g/cm3 = 1387.89 g of titanium
And molar mass of titanium = 47.88 g/mole
Then moles of titanium = 1387.89 g / 47.88 g/mol
= 28.98 moles
Now by using Avagadros number we can find number of atoms
So
Number of atoms of titanium = 28.98 moles x (6.022 x 1023 atoms/mol)
= 1.745 x 1025 atoms
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