Balanced equation for this reaction is,
3H2O + Mg3N2 --------> 3MgO + 2NH3
3 moles of H2O gives 2 moles of NH3.
1 mole of will give 2/3 moles of NH3 i.e. 0.667 moles
Moles of NH3 formed by 2.20 moles H2O = 2.20 × 0.667
= 1.467 moles
Theoretical yield = 1.467 moles
Percent yield = (actual yield/theoretical yield)×100
Actual yield = 0.823 moles
Percent yield = (0.823/1.467) × 100
= 56.0 %
Answer = 56.0 %
Ling Pool 3 Time Remaining:04:34:08 1. Consider the unbalanced equation for the following reaction: H2O(l) +...
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Time Remaining:02:39:43 1. Consider the balanced equation for the following reaction: 3LI2S(aq)+ 2Bi(NO3)3 (aq) 6LINO3(aq)+ Bl2S3(s) Determine how much excess reactant remains in this reaction if 6.13 moles of Li2S reacts with 0.143 moles of BI(NO3)3- 5.92 moles 0.072 moles 3.07 moles 0.107 moles 6.13 moles Use the slider to rate your confidence on this question. -1 100 ne Not at all confident nd Very confident app s): save submt ata) a fee The