a)
volume , V = 48 mL
= 4.8*10^-2 L
use:
number of mol,
n = Molarity * Volume
= 0.14*4.8*10^-2
= 6.72*10^-3 mol
Molar mass of KCl,
MM = 1*MM(K) + 1*MM(Cl)
= 1*39.1 + 1*35.45
= 74.55 g/mol
use:
mass of KCl,
m = number of mol * molar mass
= 6.72*10^-3 mol * 74.55 g/mol
= 0.501 g
Answer: 0.501 g
b)
Moles of KCl = 6.72*10^-3 mol
1 mol of KCl has 1 K+ ion
So,
Mol of K+ = mol of KCl
=6.72*10^-3 mol
Answer: 6.72*10^-3 mol
Please answer the questions below to three significant figures. a) What mass of KCI is required...
Please answer the questions below to three significant figures. a) What mass of KCI is required to make 47.0 mL of a 0.280 M KCl solution? 9 кСІ b) How many moles of potassium ions are present in the solution? mol
Please answer the questions below to three significant figures. a) What mass of KCl is required to make 44.0 mL of a 0.270 M KCl solution? .......... g KCl b) How many moles of potassium ions are present in the solution? ........ mol
Please answer the questions below to three significant figures. a) What mass of KCl is required to make 59.0 mL of a 0.260 M KCl solution? 1 g KCl b) How many moles of chloride ions are present in the solution?
someone please answer these questions :) 304 (94) + Pb (at) - 1604 is) c) List the spectator ions for the reaction Ng_t() 2N05 (ag) –7 M7410g) + 2ND:5194) Complete the following problems 1) For the reaction: 2KCIO: - 2 KCI + 3 Oz a) If 4.6 mole of KCIO, decomposes, how many moles of oxygen gas will be produced? b) If 0.25 mole of oxygen gas is produced, how many moles of KCl is formed? c) If 2.72 g...
DATA TO BE USED Please use the data provided below to complete this assignment. Refer to Expt. 7 in the laboratory manual for an explanation of the data. o Mass used to prepare 5.0 g/L sodium sulfate solution: 0.494 g o Mass used to prepare 0.025 M sodium sulfate solution: 0.351 g o Mass used to prepare 2.0 mM sodium sulfate solution: 0.025 g o Conductivity (in uS/cm) for 5.0 g/L and 0.025 M and 2.0 mM sodium sulfate solutions...
Part A 162g of a 31.0% (m/m)LiBr solution Express your answer to three significant figures and include the appropriate units. ? HA 49.0 g Request Answer Previous Answers Submit iIncorrect; Try Again; 4 attempts remaining Review your calculations, you may have made a rounding error or used the wrong number of significant figures Part B 492 g of a 8 5% (m/m)KCI solution Express your answer to two significant figures and include the appropriate units. Part C 286 mL of...
What is the mass, in grams, of 1.50 mol of iron (III) sulfate? Express your answer using three significant figures. How many moles of ammonium ions are in 6.935 g of ammonium carbonate? Express your answer using four significant figures. What is the mass, in grams, of 1.40 times 10^21 molecules of aspirin, C_9H_8O_4? Express your answer using three significant figures.
Express your answer to three significant figures and include the appropriate units, The formula of Benadryl is C17H21NO. How many moles of C are present in 0.752 moles of Benadryl? How many moles of H are present in 2.20 moles of Benadryl? How many moles of N are present in 1.64 moles of Benadryl?
please answer all, and type please Problems and questions (show all calculations, correct significant figures and units) 1. Why is it important to test the crucible for cracks before heating it? 2. Write the correct balanced equation for the dehydration (removal of water) of the magnesium sulfate hydrate obtained in Procedure B of this experiment. 3. How many moles are in 70.0 grams of potassium hydroxide? 4. A compound is formed when 0.300 moles of barium combine with 0.600 moles...
Please help me answer these two questions. Thanks! ------------------------------------------------------------------------------------------ ------------------------------------------------------------------------------------------ The first step in the lab will be to prepare a solution of sodium hydroxide that is approximately 0.1 M. How many mL of 50.5% NaOH (density 1.54 g/mL) will you need to prepare 250 mL of solution?* 1.032 g of the potassium iron oxalate compound was placed in the oven to dry for 1 h. The final mass of the compound was 0.919 g after drying. How many moles...