what is the probability of rolling a number greater than 1 on a regular six-sided die?
Six sided die is S={ 1, 2, 3, 4, 5, 6 }
Total event = 6
Roll | die | probability |
1 | 1/6 | 0.1667 |
2 | 1/6 | 0.1667 |
3 | 1/6 | 0.1667 |
4 | 1/6 | 0.1667 |
5 | 1/6 | 0.1667 |
6 | 1/6 | 0.1667 |
Now, we have to find P(X > 1)
Therefore,
P(X>1) = P(X=2) + P(X=3) + P(X=4) + P(X=5) + P(X=6)
P(X>1) = 1/6 + 1/6 + 1/6 + 1/6 + 1/6
P(X>1) = 5/6
P(X>1) = 0.8333
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