Question

chemistry

1. Your boss asks you to prepare and then standardize a sodium hydroxide solution, which you do as you did in this lab. The average concentration is 0.1063M. He then hands you a solution of nitric acid and asks you to titrate it with your NaOH solution. It requires 27.33mL of your tandardized NaOH solution to titrate 24.79mL of the nitric acid solution. Write a chemical quation for the neutralization reaction and then calculate the molarity of the nitric acid solution

Answer 1

Please post one question at a time.

1,

The equation is;

HNO3 + NaOH --> NaNO3 +H2O

Now since in a neutralisation reaction number of gram equivalents remain the same,

Using the formula ,

molarity of sodium hydroxide*Volume of sodium hydroxide=molarity of nitric acid*Volume of nitric acid

0.1063 x 27.33 = ? x 24.79

therefore ?= O.1063 x 27.33 / 24.79

= 0.1172M