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-3 +1 +1 +5 -2 NH3(aq) + 20%(9) ► HNO3(aq) + H20(1) The oxidation state of the nitrogen atom is – 3 before the reaction and + Can anyone tell me how to can the -3 and +5 on the of N? I know -3 to +5 is oxidized. But I don't know where is -3 and +5 come from.

+4 -2 C(s) + O2(g) → CO2(g) The oxidation state of the carbon atom is 0 before the reaction and +4 after the reaction. That mSame question how do you get 0 and +4?

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en Let the oxidation state of N oxidation state of H is t Nel charge on Nhz is o :: X+3x1 0 x+3 =0 X=-3 (le oxidation state

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