A 250 g mass attached to a horizontal spring oscillates at a frequency of 3.70 Hz . At t =0s, the mass is at x= 5.20 cm and has vx =− 29.0 cm/s . Determine: the position at t=1.60s
for the equation of SHM we can write
now it is given that at t = 0 we have x = 5.20
also we have
now at t = 0 speed v = -29 cm/s
from above two equations we have
now from 1st equation
now we have
at t = 1.60
A 250 g mass attached to a horizontal spring oscillates at a frequency of 3.70 Hz...
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