A 265 g mass attached to a horizontal spring oscillates at a frequency of 4.90 Hz. At t =0s, the mass is at x= 5.60 cm and has vx =− 31.0 cm/s. Determine the position at t= 0.600 s.
w = 2pi*4.9 = 9.8pi
X = A sin(9.8pi * t + phi)
5.60 = A sin(phi)
V = A*9.8 pi cos(9.8pi * t + phi)
-31 = A*9.8 pi cos(phi)
(-5.6/31) * (9.8 pi)= tan (phi)
phi =-79.8069417795 deg
A = 5.68980182479 cm
x(0.6)= 5.68980182479sin(9.8 pi * 0.6 -79.8069417795)
=-5.57741242039 cm
A 265 g mass attached to a horizontal spring oscillates at a frequency of 4.90 Hz....
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