A 220 g mass attached to a horizontal spring oscillates at a frequency of 3.10 Hz . At t =0s, the mass is at x= 5.00 cm and has Vx =− 17.0 cm/s .
Part E) The maximum speed.
Part F) The maximum acceleration.
Part G) The total energy.
Part H) The position at t= 5.40 s .
Amplitude = A = sqrt[(17/2 pi x 3.10) + 5^2] = 5.08 cm
Angular Frequency, w = 2 pi x 3.1 = 19.48 rad/sec
E)
Speed, v = 5.08 x 19. 48 = 98.96 cm/s
F)
Acceleration = 5.08 x 19.48^2 = 1927.29 cm/s^2
G)
E = 0.5 x 0.22 x 19.48^2 x 0.0508^2 = 0.108 J
H)
Phi = arccos(5/5.08) = 0.178 rad
Y = 5.08 cos(19.48 x 5.4 + 0.178) = 0.64 cm
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A 220 g mass attached to a horizontal spring oscillates at a frequency of 3.10 Hz...
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