Question

need to see what i did right and wrong , if possible small explanation as to what was wrong

Br 1 eneae 3 ch1so butane Ано Designate the chiral center in each molecule, if there is one, with a star efhere ntert 1) Assign 1,2,3,4 priority based on atomic number of each atom bonded to the stereogenic or chiral center. 2) Try naming C, D amd G INCLUDE R and S configuration if present 1 etlee Pentane broms 3nitril CN S h) iethere 3 pAtileprers NONC 2) What term describes the structural relationship between cis-1,2-dimethylcyclopentane and trans-1,3- dimethylcyclopentane? Draw them out. A) not isomers B) constitutional isomers C) enantiomers D) diastereomers E) conformers 3) Which of the following terms best describes the pair of compounds shown: enantiomers, diastereomers, or the same compound? BUILD THEM Dia Diasterecmers CH сО,н CrCO,H HN H CH, NH н- 4) Is the molecule shown below chiral or achiral? Explain YOUR ANSWER ACniral thisimare can be mirroreu as well as suprimposed CHE3CCHCH2 mviul asitiContains (CHs) 2groups rat are ithe same NO CHIRAL CENTER 5) Does this molecule have a mirror plane? If so, represent where the plane would be with a dashed line.

Answer 1

OBY H 1+2+3 → Antielockwise so, s. But Lowest Priority (H) group above the plane so an el I (R)-2-chloro schanges to R. 1-butene PHOSRH "(R)-3-methyl-1-Pentes 1+2+3+ Anticlockwise , so's But lowest priorit horizontal plane so 's charges to R. up

0 e) H 1-6273 clockwise. So, R. But lowest priority a group (H) Present above the plane so R changes to s. in Br 1-2-3-4 Anticlockwise. So,'S'. But lowest ① R ① priority group (H) present above the plane. So s changes to R. '3? [CR)-2-Cyano-1-bromo but-3-ene] nohem here SU - Cool - HA 43" (cis-1,2-dimethyl eyelopentane) (trans- 1,3-dimethylcyclopentane) According to above structure they have same mokadar formula bat bonding connectivity is diffement. Hence they are constitutional isomer. COOH Double -> H2N- f.coot ~ fto - exchange . NH₂ 1. Hz Therefore they are same compound, 4 This is achiral molecule because «13 (13 Carbon 1 & 2 Contain two same group which make the moleente achiral. E mirror plane CH3 12 242 SITE //