Question

4. A solution containing 0.2 g of glucose/cm3 is passed through packed bed of alumina at a flow rate of 10 cm3/s. The breakpoint concentration is set at C/Co 0.01. The breakthrough curve data obtained are given in Table 4. Table 4 Concentration at the outlet (C) (g of glucose/cm) t (min) C 10 C 20 0.01 30 0,025 40 0.05 0.07 50 60 0.1 70 0.13 80 0.15 0.175 0.19 90 100 110 0.2 0.2 0.2 120 140 160 0.2 180 FGTAJuly 2011 Mass Tranfer 2 CP8 20104 Estimate the breakpoint time, the total capacity of the bed used at breakpoint and the fraction of unused bed to the breakpoint

Answer 1

Given C₀ = 0.2g/cm³

At a time t, C₀ = C_ad + C

C_ad = Concentartion of glucose adsorbed ; C= concentration of glucose in outlet i.e,concentration of glucose not adsorbed

We need to plot t vs C_ad ,So that we could get the data asked in the question.For plotting ,first construct a table of time t, C and C_ad as below

C_ad = C₀ - C;

t Ca 0.2-C C 0 0 0.2 10 0.2 0.2 20 0 30 0.01 0.19 40 0.025 0.175 50 0.05 0.15 60 0.07 0.13 70 0.1 0.1 80 0.13 0.07 90 0.15 0.05 100 0.175 0.025 110 0.19 0.01 120 0.2 C 130 0.2 0 140 0.2 0 0.2 150 0 160 0.2 C

now plot t vs C_ad

O-19 O-18 0-17 O-16 O-15 O-14 0-13 O-12 0-11 1-0 6.09 O.07 0-06 lo:05 O-02 CS 70 time 1ohecoyitso 40 130 20 150 50 90 00 mScarrer

C o0 break point time7 Co kaes thet C- Cad are Co- Cad Co /- Cad Co O 99x O 2 0.198 g/ans the breakpoint tine corresponding lo Cad 0/98 glem3 Time - 3 min cS 3onet CamScanner get braak point time we

e.o O-18 0-17 O-16 0-15 0-14 0-13 O.12 0-11 Cad 0-1 6.09 O.08 O-07 0-06 0-03 To-O 0.0 40 50 20 30 CS

Total capauty of bed- Total gluc0se adsorbed till Saturalion arca under graph tus la fburdCad t by square counting of cach column and addins no of sguares /4 14d X-5tale s cale 14 2x /O x 0 0 of ghuosexlox 60) cod Imig = 8.520g of ghuese Total capauly 14 /- gucose uscd cp till t Total ghose capaity fraction of unused bed at th 3 min JCal dExowwFind asdt by Simlovly Gd dt xlowCounhiay squares of shaded arca 46x10r0.01 42x10x0.0 = 0.676 67.6% ESScanned with CamScanner

*we get the value of integral term from the area of graph.

Capacity at break point is glucose used up till t_b = = 46x10x0.01 x 10 x60=2760 g glucose

3 Caddt x (flow rate in cm*/min)

[[In the above graph , i have approximated Number of squares in each column and written above respective column. At the breakpoint column is divided to two columns by the breakpoint time line,and respective Number of squares in both parts of column are marked above respective parts of column].[Shaded area is area under curve till breakpoint t_b]

O-19 O-18 O-17 O-16 O-15 0-14 0-13 O 12 0.11 6.09 O.08 O-07 o-06 O.05 40- 0-03 To-O O-01 130 50 710 140 10 20 3o CamScanner 40 60 90 L00 50 time

Hope it helps and if it does plz give THUMBS UP

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