Question

A proton accelerates from rest in a uniform electnc neid of 660 N/C. At one later moment, its speed is i.30 Mm/s (nonrelativistic because v is much less than thถ speed of (a) Find the acceleration of the proton. m/s (b) Over what time interval does the proton reach this speed? c) How far does it move in this time interval? (d) What is its kinetic energy at the end of this interval?

Answer 1

Here proton is accelerated from rest therefore its initial velocity is zero. Force on a charge 'q' in uniform electric field is F = q E hence equating this force with equation F = mass x acceleration

we can find acceleration of the charge particle F = m a = q E

a = q E /m

I have calculated and shown on the sheet scanned and attached.

Further answers are obtained by using first and second equations of motion.