Question

A proton accelerates from rest in a uniform electric field of 660 N/C. At one later moment, its speed is 1.40 Mm/s (nonrelativistic because v is much less than the speed of light).

(a) Find the acceleration of the proton.
m/s²

(b) Over what time interval does the proton reach this speed?
s

(c) How far does it move in this time interval?
m

(d) What is its kinetic energy at the end of this interval?
J

Answer 1

Part a

The acceleration is $6.32 \times {10^{10}}{\rm{ m/}}{{\rm{s}}^2}$.

Part b

The time taken by proton to reach its final speed is $2.2 \times {10^{ - 5}}{\rm{ s}}$.

Part c

The distance moved by the proton in time t is 15.3 m.

Part d

The kinetic energy of proton is $1.63 \times {10^{ - 15}}{\rm{ J}}$.