Question

The skin temperature of a nude person is 32.0 °C and the surroundings are at 21.5°C. The emissivity of skin is 0.900, and the

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Р: есл(т-т.) e = 0.9 0 =5.67X 10-8 W/m2K4 A = 1.55m2 T: 32°C = 305k To = 21.5°C - 294.5k p = (0.9) * (5.67x10-8)(1.55) *[(305

Add a comment
Know the answer?
Add Answer to:
The skin temperature of a nude person is 32.0 °C and the surroundings are at 21.5°C....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 10/700 Resources Feedback The skin temperature of a nude person is 32.0°C and the surroundings are...

    10/700 Resources Feedback The skin temperature of a nude person is 32.0°C and the surroundings are at 23.0°C. The emissivity of skin is 0.915, and the surface area of the person is 1.55 m² What is the rate Pat which energy radiates from the person? P= 78.57 What is the net energy loss AE from the body in 3 min by radiation? AE = 14143

  • Part A please thanks! The skin temperature of a nude person is 32.5°C and the surroundings...

    Part A please thanks! The skin temperature of a nude person is 32.5°C and the surroundings are at 21.0°C. The emissivity of skin is 0.910, and the surface area of the person is 1.50 m². What is the rate P at which energy radiates from the person? P = 507 What is the net energy loss AE from the body in 1 min by radiation? AE = 5755.2

  • How much power (power is the energy per second) is radiated by the person

    Radiation of Energy The rate of heat transfer by emitted radiation is determined by the Stefan-Boltzmann law of radiation: = aeAT4 where o 5.67x10-8 J/s - m2 K is the Stefan-Boltzmann constant, A is the surface area of the object, and T is its absolute temperature in kelvin. The symbol e stands for the emissivity of the object, which is a measure of how well it radiates An ideal jet-black (or black body) radiator has e 1,whereas a perfect reflector has...

  • Estimate the lowest environment temperature that a person, who has skin temperature 34.0 °C, total skin...

    Estimate the lowest environment temperature that a person, who has skin temperature 34.0 °C, total skin area 1.53 m2, emissivity 0.800, and metabolic energy production 157 J/s, can stand naked without a significant drop of body temperature.

  • 10. (10pts) The surface area of an adult human being is 1,8 m2. Suppose a person with a skin tem ...

    10. (10pts) The surface area of an adult human being is 1,8 m2. Suppose a person with a skin tem omperature of 34°C is standing with bare skin in a room where the air is 22°C but the walls are 21°C. (ơ 5.67" 104 J / (sm"к"). There is a "dead ai lay ran around you next to your skin that acts as insulation. This dead-air layer is 5.0 mm thick. a) Draw b) What is the person's rate of...

  • The emissivity of the human skin is 97.0 percent. Use 35.0 °C for the skin temperature...

    The emissivity of the human skin is 97.0 percent. Use 35.0 °C for the skin temperature and approximate the human body by a rectangular block with a height of 1.81 m, a width of 40.5 cm and a length of 32.0 cm. Calculate the power emitted by the human body. 1.430x103 w You are correct. Your receipt no. is 158-4715 Previous Tries Fortunately our environment radiates too. The human body absorbs this radiation with an absorbance of 97.0 percent, so...

  • An animal's body has a skin temperature of 33 °C and is the room temperature where...

    An animal's body has a skin temperature of 33 °C and is the room temperature where the walls are at temperature 29 °C. If the emissivity is 1 and the body area is 1.5 m2. What is the rate of heat transfer by radiation? ( Stefan-Boltzmann constant = 5.67 x 10 -8 J/s m?k4) 42 W 38 W 72 W O 54 W O 63 W

  • The total surface area of the human body is 1.20 m2 and the surface temperature is...

    The total surface area of the human body is 1.20 m2 and the surface temperature is 30∘C=303∘K. If the surroundings are at a temperature of 6.0 ∘C , what is the net rate of heat loss from the body by radiation? The emissivity of the body is very close to unity, irrespective of skin pigmentation. Express your answer using two significant figures.

  • The rate of heat transfer by emitted radiation is determined by the Stefan-Boltzmann law of radiation...

    The rate of heat transfer by emitted radiation is determined by the Stefan-Boltzmann law of radiation = ceAT4 t where a 5.67x108 J/(s m2. K4) is the Stefan-Boltzmann constant, A is the surface area of the object, and T is its absolute temperature in kelvin. The symbol e stands for the emissivity of the object, which is a measure of how well it radiates. An ideal jet-black (or black body) radiator has e 1, whereas a perfect reflector has e...

  • Suppose you walk into a sauna that has an ambient temperature of 44.0°C. (a) Calculate the...

    Suppose you walk into a sauna that has an ambient temperature of 44.0°C. (a) Calculate the rate of heat transferred to you by radiation given your skin has a temperature of 37.0°C, an emissivity of 0.98, and the surface area of your body is 1.40 m2. W (b) If all other forms of heat transfer are balanced (net zero), at what rate will your body temperature increase if your mass is 64 kg? (Assume 3500 J/(kg • °C) is the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT