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PRACTICE EXERCISES SECTION MULTIPLE CHOICE Bloms and 2 Figure 14 i mole of ideal gas is brought to a final state F by one of

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Answer #1

for idea gas

PV = nRT ; n= 1 given

T = PV/R

final temperature for all is the same because they ends at the same point

Tf = P02V0 /R =2P0V0 /R

initial T for

1) Ti =  P0V0​​​​​​​ /R

2) Ti = 2P0V0​​​​​​​ /R

3) Ti = 3P0V0​​​​​​​ /R

so change in temperature   

in 1 = 2*P0V0​​​​​​​ /R -P0V0​​​​​​​ /R = P0V0​​​​​​​ /R  

in 2 = 2P0V0​​​​​​​ /R -2P0V0​​​​​​​ /R = 0

in 3 =2P0V0​​​​​​​ /R -3P0V0​​​​​​​ /R = -P0V0​​​​​​​ /R

so in process process 2 change is smallet

if we talk about magnitude not taking account the negative sign in process 3

work done by gas = Pdv = area under P- v curve so

so area under number 3 curve is smallest so work is done is also smallest  

****************************************************************************
Goodluck for exam Comment in case any doubt, will reply for sure..

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