If a thermodynamic process proceeds isochorically and 200 Joules of heat is added to the system changing its temperature by 20 degrees Celsius, what is the change in internal energy?
+10 J
+200 J
-200 J
-10 J
Since process is isochoric , that means volume is constant .
There will be zero work done at constant volume.
Hence according to thermodynamics first law, Q = dU + W
=) Q = dU at W = 0
Hence change in internal energy is +200 Joule .
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