To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest,...

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To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest,...

To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant angular acceleration, releasing the discus after making one complete revolution. The diameter of the circle in which the discus moves is about 1.7 m .

Part A

If the thrower takes 0.90 s to complete one revolution, starting from rest, what will be the speed of the discus at release?

Express your answer in meters per second.

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Answer 1

Answer #1

The radius (length of thrower's arm+hand+1/2 diam of discus) = R = 1.7/2 = 0.85 m
The length of the circular path discus travels in thrower's hand = C = 2πR = 5.34 m
we know,

Vavg =distance/time= C/t = 5.34/.900 = 5.9341 m/s
Assuming a UNIFORM angular acceleration, α, then final speed of discus = 2Vavg = 11.8682 m/s

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Answer 2

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