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P2.10 Interview question Two people, trying to meet, arrive at times independently and uniformly distributed between noon and 1pm. Find the expected length of time that the first waits for the second.
Problem 4 Do P2.10. Apply the bottom formula on P2.8. If we measure time in hours starting from noon, then each arrival time is uniformly distributed in [0,1], so the joint density of the two arrival times (x, y) is/(x, y) 1 for 0 s x s 1,0 syS 1. How to express the waiting time g (x, y) in terms of x and y? E221
Ty If (X, Y) are continuous with density f then Eg (X, Y) g(a, y)f(x, y)dzdy Expectation Variance and cov OK
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Answer #1

let

X = time of arrival of people 1

Y = time of arrival of people 2

X,Y = Unif(0,1)

we need to find

E(max(x,y) - min (x,y))

f(x,y) = 1

max (x, y) - min (x, y) dx dy 1/3

= 20 min

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