14) Consider the following information: Block 1: 600.g: C =0.200 J/°C g; initial T = ?;...

Question

Question

Answer 1

Answer #1

m(Block 1) = 600.0 g

T(Block 1) = to be calculated

m(Block 2) = 400.0 g

T(Block 2) = 70.0 oC

C(Block 2) = 0.6 J/goC

T = 50.0 oC

We will be using heat conservation equation

use:

heat lost by Block 2 = heat gained by Block 1

m(Block 2)*C(Block 2)*(T(Block 2)-T) = m(Block 1)*C(Block 1)*(T-T(Block 1))

400.0*0.6*(70.0-50.0) = 600.0*0.2*(50.0-T(Block 1))

T(Block 1)= 10 oC

Answer: d

Answer 2

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