Answer:
a).
standard error = sd/sqrt(n) = 70/sqrt(125) =6.2610
we have to find P( 292 <mean x < 308)
z value for 292, z =(292-300)/6.2610 = -1.28
z value for 308, z =(308-300)/6.2610 = 1.28
P( 292 <mean x < 308) = P( -1.28 <z<1.28)
=P( z < 1.28)-P( z < -1.28)
= 0.8997 - 0.1003
=0.7994
b).
we have to find P( 289 <mean x < 311)
z value for 289, z =(289-300)/6.2610 = -1.76
z value for 311, z =(311-300)/6.2610 = 1.76
P( 289 <mean x < 311) = P( -1.76 <z<1.76)
=P( z < 1.76)-P( z < -1.76)
= 0.9608-0.0392
=0.9216
Q Search this course Homework of 70 n ±8 of the population mean (to 4 decimals)?...
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