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2 u C 30C 2 cm 3 cm The figure shows a test charge q between the two positive charges. Find the force (in newtons) on the tes
For the previous question, find the electric field (in newtons/coulomb) at the position of the test charge. Again, supply a p
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Answer #1

Fr 2cm 3HC 2uc= 2X1oc Fon৫ of 9epulslcn to the sught due to 24c is m a to sught f= याछ (उराउ) 1e X 7 Ях 04 13 12 FI 4DN tori13 -12 XIO XI0 alx10 27x5 2 135 N to left Net fosice 9=2HC is 40-135 F -95 N Net electouic field at the locahon of iy given bE415x1 NC indicates net electouic field to the left

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