net force = force due to q2 + force due to q3
F = k q1 * ( q2 / r2^2 + q3 / r2^2)
F = 9*10^9* 10^-18* ( 2/ 0.02^2 + 6/ 0.02^2)
F = 1.8*10^-4 N
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directed along x axis, so x = 0
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do comment in case any doubt, will reply for sure . Goodluck
Exercise 21.17 Constants Part A Three point charges are located on the positive x axis of...
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