Question

- 440 N 19) If a 13 newton force is applied to a 2.5 kg christmas gin what is the a) friction force? and it travels at consta
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Since the speed is constant, acceleration will be zero. Hence from Newton’s law of motion the friction force will be equal to the applied force.19) a) f4 AME> F F - f = ma a=o because speed is const- f= F = 13 N so, b) No = mg = (2-5 kg)g = 24.5N Not Fsino = mg > => No

***********************************************************************************************
Check the answer and let me know immediately if you find something wrong or missing... I will rectify the mistakes asap if any

Add a comment
Know the answer?
Add Answer to:
- 440 N 19) If a 13 newton force is applied to a 2.5 kg christmas...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT