yf(x) is the function illustrated below, defined only on x E [0, 6]: 110 -1 Compute...
solve for L, A0, An, Bn, and f(x).
(1 point) y= f(x) is the function illustrated below, defined only on в€ (0,6): Б 10 -1. -1 Compute the Fourier coefficients for f(x). Since we are only interested in the interval 0,6|, we don't care what happens anywhere else. We can pretend the function is zero on -6,0 and periodic: 10 57 19
(1 point) y= f(x) is the function illustrated below, defined only on в€ (0,6): Б 10 -1. -1...
FIND A0, An, Bn, and f(x)
f(x) is the function illustrated below, defined only on x E [0,4]: y 4 110 -1 -1 Compute the Fourier coefficients for f(x). For this question, we will reflect the graph around the y-axis to get an even function: 1 0 -5 13 -1 We get L =4 (x)dx A0 =
f(x) is the function illustrated below, defined only on x E [0,4]: y 4 110 -1 -1 Compute the Fourier coefficients for f(x)....
y=f(x)y=f(x) is the function
illustrated below, defined only on x∈[0,6]x∈[0,6]:
Complete the Fourier Coefficients? An is incorrect.
At least one of the answers above is NOT correct. 13 of the questions remain unanswered. (1 point) yf(z is the function illustrated below, defined only on E0,6 1.e 51 Compute the Fourier coefficlents for f(x) Now compute the cosine coefficients: An f)cos ()dz dr XCos(npix/6) -( d 0 Note: You can earn partial credit on this problem. Submit Answers Preview My Answers...
y=f(x)y=f(x) is the function
illustrated below, defined only on x∈[0,4]x∈[0,4]:
Compute the Fourier coefficients for f(x)f(x).
A0=1L∫L−Lf(x)dx= ?
At least one answers above NOT correct. 14 of the questions remain unanswered. (1 point) y f() is the function illustrated below, defined only on r E0, 4: 1 e Compute the Fourier coefficients for f(r) For this questlon, we wll reflect the graph around the y-axls to get an even function: We get L4 f)dae = [-9/8 A
At least one...
solve for L, A0, An, Bn, and f(x).
f(x) is the periodic function illustrated below: y 1/0 -9 Compute the Fourier coefficients for f(x)
f(x) is the periodic function illustrated below: y 1/0 -9 Compute the Fourier coefficients for f(x)
Question 6 Consider the function defined over the interval 0<x<L. Extend f(x) as a function of period 2L by using an odd half-range expansion 1) Sketch the extended function over the interval -3L<XS3L. 2) Calculate the coefficients for the Fourier Series representation of the extended function. 3) Write the first 5 non-zero terms of the Fourier Series. (10 marks)
1. Consider the function defined by 1- x2, 0< |x| < 1, f(x) 0, and f(r) f(x+4) (a) Sketch the graph of f(x) on the interval -6, 6] (b) Find the Fourier series representation of f(x). You must show how to evaluate any integrals that are needed 2. Consider the function 0 T/2, T/2, T/2 < T. f(x)= (a) Sketch the odd and even periodic extension of f(x) for -3r < x < 3m. (b) Find the Fourier cosine series...
function is defined over (0,6) by
f(x)={14x00<xandx≤33<xandx<6.
We then extend it to an odd periodic function of period 12
and its graph is displayed below.
calculate b1,b2,b3,b4, Thanks so much
A function is defined over (0,6) by 0<x and x <3 f (x) = 3<x and x < 6 We then extend it to an odd periodic function of period 12 and its graph is displayed below. 1.5 1 у 0.5 -10 5 10. 15 -1 -1.5 The function may be...
A function is defined over (0,6) by 0 <and I <3 f(1) = - { 3<; and <6 We then extend it to an odd periodic function of period 12 and its graph is displayed below. N y 1 0 -10 5 5 10 15 X The function may be approximated by the Fourier series f (t) = a0 + 1 (an cos (021 ) + bn sin ( 122 )), where L is the half-period of the function. Use...
3. In this case, finding the deflection through direct integration would be quite diffi cult due to discontinous nature of the function. However, since we don't care about anything other than what is happening on the beam itself, we could treat the entire function y 1H (x - 3), 0< r <4 as a single cycle in a periodic function and simply disregard everything else The Fourier Series of a periodic function fr (x) defined over one period E a,...