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This question is based on metals experiment basically on metals titrations.
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Question 2 of 5 A 0.4686 g sample of pewter, containing tin, lead, copper, and zinc,...
A 0.4505 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid....
A 0.4505 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid. Tin was precipitated as SnO2⋅4H2Oand removed by filtration. The resulting filtrate and washings were diluted to a total volume of 250.0 mL. A 15.00 mL aliquot of this solution was buffered, and titration of the lead, copper, and zinc in solution required 35.10 mL of 0.001497 M EDTA. Thiosulfate was used to mask the copper in a second 20.00 mL aliquot. Titration of the...
A 0.4598 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid....
A 0.4598 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid. Tin was precipitated as SnO2·4H2O and removed by filtration. The resulting filtrate and washings were diluted to a total volume of 250.0 mL. A 20.00 mL aliquot of this solution was buffered, and titration of the lead, copper, and zinc in solution required 34.81 mL of 0.001487 M EDTA. Thiosulfate was used to mask the copper in a second 25.00 mL aliquot. Titration of...
A 0.4504 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid....
A 0.4504 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid. Tin was precipitated as SnO2⋅4H2O and removed by filtration. The resulting filtrate and washings were diluted to a total volume of 250.0 mL. A 15.00 mL aliquot of this solution was buffered, and titration of the lead, copper, and zinc in solution required 35.78 mL of 0.001478 M EDTA. Thiosulfate was used to mask the copper in a second 20.00 mL aliquot. Titration of...
Please help. I will rate! A 0.4721 g sample of pewter, containing tin, lead, copper, and...
Please help. I will rate!
A 0.4721 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid. Tin was precipitated as SnO 4 H,O and removed by filtration. The resulting filtrate and washings were diluted to a total volume of 250.0 mL. A 15.00 mL aliquot of this solution was buffered, and titration of the lead, copper, and zinc in solution required 34.45 mL of 0.001518 M EDTA. Thiosulfate was used to mask the copper in...
A 0.3304-g sample of brass (containing lead, zinc, copper, and tin) was dissolved in nitric acid....
A 0.3304-g sample of brass (containing lead, zinc, copper, and tin) was dissolved in nitric acid. The sparingly soluble SnO2.4H2O was removed by filtration, and the combined filtrate and washings were then diluted to 500.0 mL. A 10.00-mL aliquot was suitably buffered; titration of the lead, zinc, and copper in this aliquot required 34.78 mL of 0.002700 M EDTA. The copper in a 25.00-mL aliquot was masked with thiosulfate; the lead and zinc were then titrated with 25.62 mL of...
A 24-hr urine specimen was diluted to exactly 2.000 L in a volumetric flask. The Ca^2+...
A 24-hr urine specimen was diluted to exactly 2.000 L in a volumetric flask. The Ca^2+ and Mg^2+ in a 100.0-mL aliquot of the diluted solution required 20.81 mL of 0.00830 M EDTA, after being buffered to a pH of 10.0. The Ca^2+ second 100.0-mL aliquot was precipitated as CaC_2O_4(s), which was filtered and washed. The filtrate and washings were titrated with 5.98 mL of the EDTA solution. Calculate the milligrams of Ca^2+ and Mg^2+ in the 24-hr sample.
1. A 0.7336-g sample of an alloy containing copper and zinc is dissolved in 8 M...
1. A 0.7336-g sample of an alloy containing copper and zinc is dissolved in 8 M HCl and diluted to 100 mL in a volumetric flask. In one analysis, the zinc in a 25.00-mL portion of the solution is precipitated as ZnNH4PO4, and subsequently isolated as Zn2P2O7, yielding 0.1163 g. The copper in a separate 25.00-mL portion of the solution is treated to precipitate CuSCN, yielding 0.1931 g. Calculate the %w/w Zn and the %w/w Cu in the sample.
Mass of antacid in sample: 1.5558 g Antacid tablet: 1.6010 g Composition of antacid: Aluminum hydroxide:...
Mass of antacid in sample: 1.5558 g Antacid tablet: 1.6010 g Composition of antacid: Aluminum hydroxide: 160 mg Magnesium carbonate: 105 mg Protocol A: Pipet a 10.00 mL aliquot of the antacid sample solution into a 125 mL Erlenmeyer flask followed by adding about 10 mL of the bicarbonate-carbonate buffer solution (pH 10.0 ± 0.1). Transfer quantitatively a 34.96 mL aliquot of standard EDTA solutioN, 0.01000 M, to the flask using a buret. Boil gently the mixture for 5 min....
Chromel is an alloy composed of nickel, iron, and chromium. A 0.6445-g sample was dissolved and...
Chromel is an alloy composed of nickel, iron, and chromium. A 0.6445-g sample was dissolved and diluted to 250.0 mL. When a 50.00-mL aliquot of 0.05173 M EDTA was mixed with an equal volume of the diluted sample, all three ions were chelated, and a 5.23-mL back-titration with 0.06139 M copper(II) was required. The chromium in a second 50.0-mL aliquot was masked through the addition of hexamethylenetetramine; titration of the Fe and Ni required 38.95 mL of 0.05173 M EDTA....
A 0.450 g sample of impure CaCO, (s) is dissolved in 50.0 mL of 0.150 M...
A 0.450 g sample of impure CaCO, (s) is dissolved in 50.0 mL of 0.150 M HCl(aq). The equation for the reaction is CaCO,(s) + 2 HCl(aq) — CaCl, (aq) + H, 0(1) + CO2(g) The excess HCl(aq) is titrated by 4.85 mL of 0.125 M NaOH(aq) Calculate the mass percentage of Caco, (s) in the sample. mass percentage: The zinc content of a 1.03 g ore sample was determined by dissolving the ore in HCl, which reacts with the...
Please help. I will rate!
A 0.4721 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid. Tin was precipitated as SnO 4 H,O and removed by filtration. The resulting filtrate and washings were diluted to a total volume of 250.0 mL. A 15.00 mL aliquot of this solution was buffered, and titration of the lead, copper, and zinc in solution required 34.45 mL of 0.001518 M EDTA. Thiosulfate was used to mask the copper in...
A 24-hr urine specimen was diluted to exactly 2.000 L in a volumetric flask. The Ca^2+ and Mg^2+ in a 100.0-mL aliquot of the diluted solution required 20.81 mL of 0.00830 M EDTA, after being buffered to a pH of 10.0. The Ca^2+ second 100.0-mL aliquot was precipitated as CaC_2O_4(s), which was filtered and washed. The filtrate and washings were titrated with 5.98 mL of the EDTA solution. Calculate the milligrams of Ca^2+ and Mg^2+ in the 24-hr sample.
A 0.450 g sample of impure CaCO, (s) is dissolved in 50.0 mL of 0.150 M HCl(aq). The equation for the reaction is CaCO,(s) + 2 HCl(aq) — CaCl, (aq) + H, 0(1) + CO2(g) The excess HCl(aq) is titrated by 4.85 mL of 0.125 M NaOH(aq) Calculate the mass percentage of Caco, (s) in the sample. mass percentage: The zinc content of a 1.03 g ore sample was determined by dissolving the ore in HCl, which reacts with the...
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