Question

Hello,

I have been struggling with one of my biology maths questions. It involves calculating enzyme activity and makes use of Beer's Law.

Question: Calculate enzyme activity using your higher Vmax value. Molar extinction coefficient: 18,300 M-1 cm-1. Work out the concentrations of product/min and find the maximum rate in μmol/min.

The equation I was given for the calculation: A=Ɛcd

Vmax: 0.4 Abs/min

Total sample volume: 3ml and enzyme was kept constant at 0.2 ml.

Length of light path: 1cm

Thank you.

Answer 1

The solution has been provided below, hope it helps :)

A= Ecd E= 18, 300 he s'im" ce ? d = lcm A = 0.4 Abs/min (= M/min 0.4 18,300 X 1 2 0.0000.21858 Menit / min 20185 x 105 = 21.85 x 10-6 Mosch /min = 21.85 M Mon 1 min Rast Rate a concentration. Rate= K [c ] = KX 21.85x10-6 k a rente constant of the reaction, which isn't provided here. Just multiply it with concentraction and you'll get the rate.