Q1:
Abs = c.l
0.89 = 7500 Lmol-1.cm-1 × c × 1.0 cm
c = 1.187×10-4 mol/L
Concentration = 1.2×10-4 mol/L (Answer)
Q2:
Abs = 1.75 is not a reliable data .
To improve the data , we need to dilute the solution so that Abs should be less than 1 .
Q3:
For dilution, water is added , the number of moles of solute remains same . We can apply M1V1 = M2V2
0.50M × V1 = 1.5×10-2 M × 100.0ml
V1 = 3.0 ml
The stock solution required = 3.0ml. (Answer)
Q4:
Abs = .c.l
0.28 = 18200M-1cm-1 × c × 1cm
c = 1.538×10-5 M
Concentration of drug in the urine = 1.538×10-5M ×(15.00ml/10.00ml ) = 2.3×10-5 M
The concentration of drug is less than 5×10-5 M , hence we can conclude that the person is not using illegal drugs .
I need help doing just the questions, not the graph or the conclusion F17 MATERIALS 0.12...
F17 UTA-401 4. A test for drug use involves ad residue is present in the sample the solution Because other things in urine may give sig concentration of 5.0x10 M drug residue in drug use involves addition of 10.00 mL of colorless reagent to 10.00 mL urine. If drug it in the sample the solution turns blue (A max = 605 nm, ε = 18,200 M'cm). ngs in urine may give slightly positive results, only tests that measure a minimum...
Percent by mass of dye in Fruit Loops cereal 11.56*100 QUESTIONS: 1. If the molar extinction coefficient (E) of a compound is 2.5 x 108 moli'cmat $28 nm and the Abs Cat 528 nm) 0.254 Dind the concentration of that solution. (assume a path length of 1.0 cm) 2. If a student measures a sample that gives an Abs = 1.85 at the 2max, is this data reliable? If not, then what might they do to improve their data? 3....
A test for drug use involves addition of 5.00mL of colorless reagent to 10.00 mL urine.If drug residue is present in the sample the solution turns blue(λmax = 605 nm, ε = 18,200M-1cm-1). Because other things in urine may give slightly positive results, only tests that measure a minimum concentration of 5.0 x 10-5 M drug residue in the original urine sample are considered positive for illegal drugs. When you measure the sample using the test described above and get...
4. A test for drug use involves addition of 10.00 mL of colorless reagent to 10.00 mL urine. If drug residue is present in the sample the solution turns blue ( 605 nm, <= 18,200 M-'cm'). Because other things in urine may give slightly positive results only tests that measure a minimum concentration of 5.0x10° drug residue in the original urine sample are considered positive for illegal drugs. When you measure the sample using the test described above and get...
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