Question


F17 MATERIALS 0.12 g [Fe(phen)3]Cl2 (students red crystals from the previous experiment) 0.5 mL unknown [Fe(phen)3]Cl2 solut
A. Series of Dilutions: Concentration of stock solution 3.15x103M 105gx mol 667.354 IL 0.05004 Concentrations of the series o
F17 UTA-709 B. Construct a Beers Low plot by graphing absorbance vs concentration. Be sure to include the point(0,0) since yo
F17 UTA-709 3. If your stock solution has a concentration of 0.50 M and you want to make 100.0 mL of a solution that has a co

I need help doing just the questions, not the graph or the conclusion
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Answer #1

Q1:

Abs = \epsilon c.l

0.89 = 7500 Lmol-1.cm-1 × c × 1.0 cm

c = 1.187×10-4 mol/L

Concentration = 1.2×10-4 mol/L (Answer)

Q2:

Abs = 1.75 is not a reliable data .

To improve the data , we need to dilute the solution so that Abs should be less than 1 .

Q3:

For dilution, water is added , the number of moles of solute remains same . We can apply M1V1 = M2V2

0.50M × V1 = 1.5×10-2 M × 100.0ml

V1 = 3.0 ml

The stock solution required = 3.0ml. (Answer)

Q4:

Abs = \epsilon.c.l

0.28 = 18200M-1cm-1 × c × 1cm

c = 1.538×10-5 M

Concentration of drug in the urine = 1.538×10-5M ×(15.00ml/10.00ml ) = 2.3×10-5 M

The concentration of drug is less than 5×10-5 M , hence we can conclude that the person is not using illegal drugs .

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