To work out the fraction you need to work out the volume of the
proton and the volume of the atom. Because the electron around the
proton is orbiting it forms a spherical electron density (A sphere)
although at any set time its just a particle around the
proton.
volume = (4/3) x PI x (r (to the power of 3))
Volume of atom = 4/3 x pi x 52.9pm x 52.9pm x
52.9pm=620091.2818
Volume of proton = 4/3 x pi x 1.0 X 10^-13cm x 1.0 X 10^-13cm x 1.0
X 10^-13cm= 4.19X10^-39
Vol fraction = (volume of proton / Volume of atom) x 100%
=6.76X10^-43
The single proton that forms the nucleus of the hydrogen atom has a radius of approximately...
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The single proton that forms the nucleus of the H atom has a radius of approximately 1.0 x 10^-13 cm. The H atom itself has a radius of approximately 52.0 pm. What fraction of the space within the atom is occupied by the nucleu? first convert 52.9 pm to cm 52.9 pm (1cm/1x10611pm) = 5.29 x 10^-10 cm Then find the volumes v proton = 4.19 x 10^-39 cm^3 v of atom 4.65 x 10 ^-28 cm^3 Dividing them gave...
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The single proton that forms the nucleus of the hydrogen atom has a radius of approximately 1.0x10^-13cm . The hydrogen atom itself has a radius of approximately52.9pm.
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In the Bohr model of the hydrogen atom, an electron orbits a proton (the nucleus) in a circular orbit of radius 0.52x10-10 m. (a) What is the electric potential at the position of the electron's orbit due to the proton? (b) What is the kinetic energy of the electron? Express the result in eV and J. (c) What is the total energy of the electron in its orbit? Express the result in eV and J. (d) What is the ionization...
In the Bohr model of the hydrogen atom, an electron orbits a proton (the nucleus) in a circular orbit of radius 0.52x10-10 m. (a) What is the electric potential at the position of the electron's orbit due to the proton? (b) What is the kinetic energy of the electron? Express the result in eV and J. (c) What is the total energy of the electron in its orbit? Express the result in eV and J. (d) What is the ionization...