Given 6 MGD of waster water with 0.9 mg/ l Dissolve oxygen concentration.
ie Given 7.48 G = 1 ft^3
ie 6 MGD = 1/7.48*6 Mft^3 / Day = 0.802 MFt^3/Day
So dissolved oxygen in waster water = 0.802*0.9 =
0.72 MFt^3/Day mg/L
Rivers initial flow rate = 40 *(60*60*24) = 3.456 MFT^3/Day
River's initial dissolved oxygen concentration =
40 *11.3 *(60*60*24)=39.05 MFT^3/Day mg/L
So oxygen contentent of river immediately after mixing
= (0.72+39.05)/( 0.802+3.456) =9.34 mg/L
6 MGD of wastewater with a dissolved oxygen concentration of 0.9 mg/L is discharged to a...
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