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Considering Kaſhydrogen cyanide) = 6.2x10-10, Kaloxalic acid) = 5.6x10-2, and K(NH3) = 1.8x10-5, hydrolysis of ammonium oxalaWhy is the following true? Thank you

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Answer #1

The conjugate acid of weak base NH4OH is NH4+ (strong)

The conjugate base of weak acid C2H2O4 is C2O42- (strong)

. Since both NH4+ and C2O42- are strong they undergo hydrolysis according to the following equation,

NH4+ + H2O    <-----------> NH4OH(aq) + H+(aq)

C2O42-(aq) + 2H2O <----------> H2C2O4(aq) + 2OH-(aq)

pH of (NH4)2C2O4 = 7+1/2[pKa-pKb)

                     = 7+ 1/2(-log(5.6*10^-2)+log(1.8*10^-5)

                     = 5.25

Therefore, the nature of the solution of ammonium oxalate is acidic because pH = 5.25 < 7


---The conjugate acid of weak base NH4OH is NH4+ (strong)

The conjugate base of weak acid HCN is CN- (strong)

. Since both NH4+ and CN- are strong they undergo hydrolysis according to the following equation,

NH4+ + H2O    <-----------> NH4OH(aq) + H+(aq)

CN-(aq) + H2O <----------> HCN(aq) + OH-(aq)

pH of NH4CN = 7+1/2[pKa-pKb)

                     = 7+ 1/2(-log(6.2*10^-10)+log(1.8*10^-5)

                     = 9.23

Therefore, the nature of the solution of ammonium cyanide is acidic because pH = 9.23 > 7

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