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2. 50 g of an unknown material is heated to 90 °C and added to 200 g of water at 25 °C. The system reaches thermal equilibriu
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Answer #1


3) let the specific heat of unknown material is S

heat lost by unknown material = heat gain by water

50 * S * (90 - 25.9) = 200 * 4.186 * (25.9 - 25)

solving for S

S = 0.235 J/(gm.K)

the specific heat of the unknown material is D) 0.235 J/(gm.K)

4)

for the heat needed to be removed

heat needed = m * L

heat needed = 4.5 * 3.33 *10^5

heat needed = 1.5 *10^6 J

the heat needed to be removed is C) 1.5 *10^6 J

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