3) let the specific heat of unknown material is S
heat lost by unknown material = heat gain by water
50 * S * (90 - 25.9) = 200 * 4.186 * (25.9 - 25)
solving for S
S = 0.235 J/(gm.K)
the specific heat of the unknown material is D) 0.235 J/(gm.K)
4)
for the heat needed to be removed
heat needed = m * L
heat needed = 4.5 * 3.33 *10^5
heat needed = 1.5 *10^6 J
the heat needed to be removed is C) 1.5 *10^6 J
2. 50 g of an unknown material is heated to 90 °C and added to 200...
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