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11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
A diverging lens has a focal length of magnitude 21.2 cm. (a) Locate the images for...
A diverging lens has a focal length of magnitude 21.2 cm. (a) Locate the images for each of the following object distances. 42.4 cm distance cm location ---Select---in front of the lensbehind the lens 21.2 cm distance cm location ---Select---in front of the lensbehind the lens 10.6 cm distance cm location ---Select---in front of the lensbehind the lens (b) Is the image for the object at distance 42.4 real or virtual? real virtual Is...
A 20 cm tall object is located 70 cm away from a diverging lens that has...
A 20 cm tall object is located 70 cm away from a diverging lens
that has a focal length of 20 cm. Use a scaled ray tracing to
answer parts a-d.
a. Is the image real or virtual?
b. Is the image upright or inverted?
c. How far from the lens is the image?
d. What is the height of the image?
e. Now use the thin lens equation to calculate the image
distance and the magnification equation to determine...
Consider a spherical mirror and lens separated by 45 cm. The mirror is on the left...
Consider a spherical mirror and lens separated by 45 cm. The mirror is on the left with a focal length of 100 cm. The lens is on the right with a focal length of −20 cm. A 5 cm tall object is placed 20 cm to the left of the lens. a) If you only consider the rays that move to the right from the object, fully characterize the final image in the system. In other words provide final image...
1.) An object is placed in front of a diverging lens with a focal length of...
1.) An object is placed in front of a diverging lens with a focal length of 17.7 cm. For each object distance, find the image distance and the magnification. Describe each image. (a) 35.4 cm location _____cm magnification _____ nature real virtual upright inverted (b) 17.7 cm location _____ cm magnification _____ nature real virtual upright inverted (c) 8.85 cm location _____ cm magnification _____ nature real virtual upright inverted 2.) An object is placed in front of a converging lens...
A converging lens with a focal length of 4.9 cm is located 20.9 cm to the...
A converging lens with a focal length of 4.9 cm is located 20.9 cm to the left of a diverging lens having a focal length of -11.0 cm. If an object is located 9.9 cm to the left of the converging lens, locate and describe completely the final image formed by the diverging lens. a) Where is the image located as measured from the diverging lens? b) What is the magnification? c) Also determine, with respect to the original object...
A diverging lens has a focal length of magnitude 16.6 cm. (a) Locate the images for...
A diverging lens has a focal length of magnitude 16.6 cm. (a) Locate the images for each of the following object distances. 33.2 cm distance cm location 16.6 cm distance cm location 8.3 cm distance cm location (b) Is the image for the object at distance 33.2 real or virtual? real virtual Is the image for the object at distance 16.6 real or virtual? real virtual Is the image for the object at distance...
Two converging lenses, each having a focal length equal to 11.0 cm, are separated by 36...
Two converging lenses, each having a focal length equal to 11.0 cm, are separated by 36 cm. An object is 22 cm to the left of the first lens. a) Findthe position of the final image using both a ray diagram and the thin-lens equation. cm to the right of the object (b) Is the final image real or virtual? O real O virtual Is the final image upright or inverted? O upright O inverted (c) What is the overall...
A diverging lens has a focal length of magnitude 22.6 cm. (a) Locate the images for...
A diverging lens has a focal length of magnitude 22.6 cm. (a) Locate the images for each of the following object distances. 45.2 cm distance cm location (behind or in front of lens) 22.6 cm distance cm location (behind or in front of lens) 11.3 cm distance cm location (behind or in front of lens) (b) Is the image for the object at distance 45.2 real or virtual? Is the image for the object at distance 22.6 real or virtual?...
A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal...
A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position cm height cm Is the image inverted or upright? O upright inverted Is the image real or virtual? Oreal virtual
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
A 20 cm tall object is located 70 cm away from a diverging lens
that has a focal length of 20 cm. Use a scaled ray tracing to
answer parts a-d.
a. Is the image real or virtual?
b. Is the image upright or inverted?
c. How far from the lens is the image?
d. What is the height of the image?
e. Now use the thin lens equation to calculate the image
distance and the magnification equation to determine...
Two converging lenses, each having a focal length equal to 11.0 cm, are separated by 36 cm. An object is 22 cm to the left of the first lens. a) Findthe position of the final image using both a ray diagram and the thin-lens equation. cm to the right of the object (b) Is the final image real or virtual? O real O virtual Is the final image upright or inverted? O upright O inverted (c) What is the overall...
A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position cm height cm Is the image inverted or upright? O upright inverted Is the image real or virtual? Oreal virtual
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