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Two solutions, A and B, are labeled "0.20 M CaCl2" and "0.40 M CaCl2", respectively. Both...

Two solutions, A and B, are labeled "0.20 M CaCl2" and "0.40 M CaCl2", respectively. Both solutions contain the same number of moles of CaCl2. If solution A has a volume of 100.0 mL, what's the volume of solution B, in mL?
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Answer #1

Moles of CaCl2 in A = M(CaCl2) in A * V(CaCl2) in A

= 0.20 M * 0.100 L

= 0.020 mol

Moles of CaCl2 in B = M(CaCl2) in B * V(CaCl2) in B

0.020 mol = 0.40 M * V(CaCl2) in B

V(CaCl2) in B = 0.050 L

= 50 mL

Answer: 50 mL

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