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(4) In a Youngs double-slit experiment, the light has a wavelength of 510 nm and the slit separation distance is 3.0 pm. Fin
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Answer #1

To obtain destructive interference for a double slit, the path difference must be half integral multiple of the wavwlength,

d sin \Theta = ( m +1/2 ) \lambda

\lambda - wavelength of the light

d - distance between the slits

\Theta - angle

m - order of interference

3000 sin \Theta = (1+1/2) 510

\Theta = 14.77 degrees

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