Calculate the probability of the following events:
C = the sum of the digits is less than or equal to 6
D = the sum of the digits is greater than or equal to 7
P(C)
P(D)
P(C or D)
P(C and D)
2 Dice Sample Space
1,1 | 1,2 | 1,3 | 1,4 | 1,5 | 1,6 |
2,1 | 2,2 | 2,3 | 2,4 | 2,5 | 2,6 |
3,1 | 3,2 | 3,3 | 3,4 | 3,5 | 3,6 |
4,1 | 4,2 | 4,3 | 4,4 | 4,5 | 4,6 |
5,1 | 5,2 | 5,3 | 5,4 | 5,5 | 5,6 |
6,1 | 6,2 | 6,3 | 6,4 | 6,5 | 6,6 |
(a)
P(C) = P(Sum of the digits 6) = 15/36 = 0.4167
So,
Answer is:
0.4167
(b)
P(D) = P(Sum of the digits 7) = 21/36 = 0.5833
So,
Answer is:
0.5833
(c)
P(C or D) = P(Sum of digits 6 OR Sum of digits 7) = 1
So,
Answer is:
1
(d)
P(C and D) = P(Sum of digits 6 AND Sum of digits 7)= 0
So,
Answer is:
0
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