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If a coin is tossed 5 times, and then a standard six-sided die is rolled 4 times, and finally a group of two cards are drawn from a standard deck of 52 cards without replacement, how many different outcomes are possible?

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we know that coin has two possible outcomes, i.e. head and tails

So, tossing 5 times, gives us a total outcome = 25 = 2 * 2 * 2 * 2 * 2 = 32

We know that the dice has 6 possible outcomes, i.e. 1,2,3,4,5,6

So, rolling die 4 times gives us a total outcome = 64-6*6*6*6=1296

We know that there are 52 cards in a deck

we have to select 2 cards at a time, i.e. combination problem with r =2 and n =52

So, number of ways = C(52, 2)52!/(52 -2)! *2!1326

Total number of possible outcomes = multilication of all three possible values from three cases

setting the values, we get

Total number of possible outcomes = 32*1296*1326 = 54,991,872 ways

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