Question

(twas. Two point charges are placed at two of the corners of a triangle as shown in the figure (Take qi electric field at the third corner of the triangle. 1.07e+07 N/C at 71.20 -11.3 nC and q2 1 5.4 μC.) Find the magnitude and the direction of the above the -x-axis) 9 10.0 cm 42 20.0 cm

Answer 1

Let E1 be field due to q1 and E2 be field due to q2,

E1 = kq1/r1^2 = 9e9*11.3e-6/0.10^2 = 10170000 N/C upward

E2 = kq2/r2^2 = 9e9*15.4e-6/0.20^2 = 3465000 N/C in -x direction

Net E = sqrt(3465000^2+10170000^2)

= 10744073 N/C

or 1.07e+07 N/C answer

  direction = arctan(10170000/3465000) = 71.2 degree above -x axis