Question

452 mothers were classified according to their alcohol intake (ounces per day) prior to pregnancy recognition and their nicotine intake during pregnanccy (milligrams per day). The data are summarized below, where 'alcnone' denotes no alcohol, 'alc001 denotes 0.01-0.10 ounces, 'alc011' denotes 0.11-0.99 ounces, and 'alc100 denotes 1.00 or more ounces. 'nin01' denotes 1-15 mg., 'nic16' denotes 16 or more mg., and 'nicnone' denotes no nicotine. Consider this to be a simple random sample from some particular population. nic01 nic16 All alcnone alc001 alc011 alc100 All nicnone 105 58 84 123 76 163 90 452 13 37 16 65 17 83 Select all that are true We know that the selected mother is one of the heavy smokers (nic16). The probability that she is also a drinker (alc001 or alc011 or alc100) equals 0.867 The probability that the selected person is a heavy-drinker (alc100) is equal to 0.199 (3 decimal places). Suppose we want to estimate the proportion of the non-smoker mothers (nicnone) among the non-drinking mothers (alcnone). This proportion can be estimated using the above information. The probability that the selected person is a heavy-drinker (alc100) and a non-smoker (nicnone) equals 0.013. The estimate of the proportion of mothers who are either heavy-drinkers (alc100) or heavy smokers (nic16) is equal to 156/452

Answer 1