1)
For given n,
Number of electron = 2n^2
= 2*3^2
= 2*9
= 18
Answer: 18
2)
For n=4, l can be 0, 1 or 2
For l=0 and ml = 0, there are 2 electrons
For l=1 and ml = 0, there are 2 electrons
For l=2 and ml = 0, there are 2 electrons
So, there are total of 6 electrons ion n=4 and ml = 0
Answer: 6
3)
For given n and l,
Number of orbitals = (2l+1)
= 2*1+1
= 3
In these 3 orbitals, there will be 3 electrons with ms=+1/2 and 3 electrons with ms=-1/2
Answer: 3
4)
For given n and l,
Number of electrons = 2*(2l+1)
= 2*(2*0+1)
= 2*1
= 2
Answer: 2
5)
n, l and ml can represent only 1 orbitals.
It can have maximum of 2 elections
Answer: 2
1.4 (6pts). What is the maximum number of electrons in a atom that can have the...
please show work on paper 1.4 (6pts). What is the maximum number of electrons in a atom that can have the following set of quantum numbers? Note: if the space contains (---) no quantum number is assigned m #electrons
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Give the maximum number of electrons in an atom that can have these quantum numbers. (a) n = 4 (b) n = 2, 1 = 2 (c) n = 4, l = 0, m, = 0 (d) n = 3 (e) n = 2, l = 1, me = -1, ms = -1/2
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