According to Coulomb’s Law, a charge Q sitting at the origin will exert a force kQq/r2 on a point charge q located at r, with the force along the r direction. The electric field E at r due to Q is equal to the force experienced by a unit charge (i.e., q = 1 unit) at r. Based on these two pieces of information, one can conclude that the magnitude of E at r is
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Answer)
Option 2) Electric field, E= kQ/r
Since, q=1 unit
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According to Coulomb’s Law, a charge Q sitting at the origin will exert a force kQq/r2...
There is an electric potential energy (EPE) between a charge Q sitting at the origin and a point charge q located at r: EPE = kQq/r, which, unlike the electric force, is a scalar quantity. The electric potential V produced by Q at r is equal to the potential energy of a unit charge at r. Based on these two pieces of information, one can conclude that the magnitude of V at r due to Q is Question 2 options: 1) kq/r2....
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A positive charge Q, located at the origin, produces an electric potential V = kQ/r at point r. A point charge q is moved from 4r to r. The increase in its electric potential energy is Question 19 options: a) 2kQq/(3r). b) kQq/(2r). c) kQq/(4r). d) kQq/(3r). e) kQq/r. f) 3kQq/(4r).
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ow let’s apply Coulomb’s law and the superposition principle to calculate the force on a point charge due to the presence of other nearby charges. Two point charges are located on the positive x axis of a coordinate system. Charge q1=3.0nC is 2.0 cm from the origin, and charge q2 = -7.0 nC is 4.0 cm from the origin.1. What is the total force (magnitude and direction) exerted by these two charges on a third point charge q3=5.0nC located at...
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