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A positive charge Q sitting at the origin will produce an electric field of kQ/r2 at...

A positive charge Q sitting at the origin will produce an electric field of kQ/r2 at r in the radial direction. The electric field (E) at (1.00 m, 0 m) produced by 1.00 C sitting at the origin is...what? (k = 8.99 x 10^9).

The electric field E at a point is equal to the force experienced by a unit charge at that point. If the electric field E at (1.0 m, 0 m) is 4.5 N/C in the +x direction, what is the electric force experienced by a point charge q = 0.0023 C at that point?

If you're able to answer, please explain!

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Answer #1

The ele ic Held Due to point chare at distancex ar^e u s positixc - 0% If is he gativeThe electric field at þoint 뼈 (1.om, o) due to charge :1c sitting at E K@ 8.99 x1ogx1-8.5g×10 Electric field-electric field ataport is e70๘ to the fra expenenced by a unit charge at Haトトoint,that is E- F IS ECt.o,o) - 4.5 NIC E=4-5必 T ce experienced by 2 O. ol035 Newto Aaon as

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