Question

Problem 2.51 Constants| Periodic Table Part A During the complicated sequence that landed the rover Curiosity on Mars in 2012, the spacecraft reached an altitude of 142 m above the Martian surface, moving vertically downward at 32.0 m/s. It then entered a so- called constant deceleration (CD) phase, during which its velocity decreased steadily to 0.75 m/s while it dropped to an altitude of 23 m What was the magnitude of the spacecrafts acceleration during this CD phase? Express your answer with the appropriate units a- Value Units Submit Request Answer ab Provide Feedback Next> 8E

Answer 1

Given that Initial velocity u = 32 m/s, final velocity v = 0.75 ms Displacement s = 142 - 23 = 119 m we know that v^2 = u^2 + 2as Substituting values 0.75^2 = 32^2 + 2 times 9 times 119 0.56 = 1024 + 238 a a = 0.56 - 1024/238 a = -4.3 m/s^2 Magnitude of acceleration a = 4.3 m/s^2