Based on the thermodynamic properties provided for water, determine the energy change when the temperature of...

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Based on the thermodynamic properties provided for water, determine the energy change when the temperature of 1.25 kg of wate

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Answer 1

Answer #1

Ti = 121.0 oC

Tf = 19.0 oC

Cg = 33.6 J/mol.oC

Lets convert mass to mol

Molar mass of H2O = 18.016 g/mol

number of mol

n= mass/molar mass

= 1250.0/18.016

= 69.3828 mol

Heat released to convert vapour from 121.0 oC to 100.0 oC

Q1 = n*Cg*(Ti-Tf)

= 69.3828 mol * 33.6 J/mol.oC *(121-100) oC

= 48956.4831 J

Lv = 40.67KJ/mol =

40670J/mol

Heat released to convert gas to liquid at 100.0 oC

Q2 = n*Lv

= 69.3828 mol *40670 J/mol

= 2821797.2913 J

Cl = 75.3 J/mol.oC

Heat released to convert liquid from 100.0 oC to 19.0 oC

Q3 = n*Cl*(Ti-Tf)

= 69.3828 mol * 75.3 J/mol.oC *(100-19) oC

= 423186.3344 J

Total heat released = Q1 + Q2 + Q3

= 48956.4831 J + 2821797.2913 J + 423186.3344 J

= 3293940 J

= 3294 KJ

Since it is heat released, please enter your answer with negative sign

Answer: -3294 KJ

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Answer 2

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