95% z-interval or t-interval Part a and b Find the 95% z-interval or t-interval for the...
95% confidence interval (PART A and B) Find the 95% z-interval or t-interval for the indicated parameter. (a) μ x 151, s-36, n-32 (b) p p=0.7, n=50 (a) The 95% confidence interval for μ is to (Round to two decimal places as needed.)
X 15.1.45 Find the 95% z-interval or t-interval for the indicated parameter. (a) u (b) p x = 153, s = 34, n=29 p=0.3, n= 60 (a) The 95% confidence interval for u is ( (Round to two decimal places as needed.) to
do parts a) & b) Find the 95% z-interval or t-interval for the indicated parameter. (a)u X- 138, s 35, n 34 (b)p p 0.3, n-62 (a) The 95% confidence interval for μ is to (Round to two decimal places as needed.) L1
Determine the margin of error for a 95% confidence interval to estimate the population mean when s=37 for the sample sizes below. Solve for c) n=46. htmathe Student Homework Theme =41778etod y FALL 2019 STAT 3309 CRN 120961 Homework: Section 8.3 Confidence intervals with s Homework Score: 0 57 of 1 pt 28.3.22-T Determine the margin of error for a 95% confidence interval to estimate the E a) n. 13 b) n = 30 c) n46 a) The margin of...
find z sc Construct the confidence interval for the population mean μ 0.95, x 5.2, σ 0.4, and n 58 A 95% confidence interval for μ is D (Round to two decimal places as needed)
part B & C? Question Help % 7.2.10 A random sample of 92 observations produced a mean x 25.9 and a standard deviation s 2.4 a. Find a 95% confidence interval for u b. Find a 90% confidence interval for c. Find a 99% confidence interval for a. The 95% confidence interval is (25 4 26.4 (Use integers or decimals for any numbers in the expression. Round to two decimal places as needed.) b. The 90% confidence interval is (...
second part: What assumptions need to be made about this population? Construct a 95% confidence interval to estimate the population mean using the data below, X = 22 s=4.8 n 18 What assumptions need to be made about this population? The 95% confidence interval for the population mean is from a lower limit of (Round to two decimal places as needed.)
part 1. A student was asked to find a 95% confidence interval for the proportion of students who take notes using data from a random sample of size n = 79. Which of the following is a correct interpretation of the interval 0.12 < p < 0.32? There is a 95% chance that the proportion of notetakers in a sample of 79 students will be between 0.12 and 0.32. There is a 95% chance that the proportion of the population...
Find a confidence interval for μ assuming that each sample is from a normal population. (Round the value of t to 3 decimal places and your final answers to 2 decimal places.) (a) x⎯⎯ x ¯ = 25, s = 5, n = 7, 90 percent confidence. The 90% confidence interval is to (b) x⎯⎯ x ¯ = 50, s = 4, n = 19, 99 percent confidence. The 99% confidence interval is to (c) x⎯⎯ x ¯ = 121,...
Given the following data, assess the 95% confidence interval. Use Table B to find the t-score. X ̅= 10, s = 2, and N = 30 TD 0 Insert Table Chart Text Shape Media Comment 10. Given the following data, assess the 95% confidence interval. Use Table B to find the t-score. *Worth 3 points. (Show your work or you will not receive full credit.) X-10, s = 2, and N = 30