Question

Add curved arrows to the reactants to show the formation of new bonds and the breaking of old bonds for the following Diels-Alder reaction. A double-barbed curve is used to represent the movement of a pair of electrons. The two solid wedges are suppose to be H's not methyl groups.

Add curved arrows to the reactants to show the formation of new bonds and the breaking of old bonds for the following Diels-Alder reaction. A double-barbed curve is used to represent the movement of a pair of electrons. The two solid wedges are suppose to be H's not methyl groups.

Answer 1

Concepts and reason

A Diels–Alder reaction is a [4 + 2] cycloaddition reaction between a conjugated diene and dienophile (substituted alkene or alkyne) to form a substituted cyclohexene. This reaction takes place in a single step with no intermediates in this reaction.

Fundamentals

A compound with a conjugated double bond in a system is represented as a diene.

A substituted alkene or alkyne is represented as a dienophile.

A Diels–Alder reaction follows a concerted, mechanistic pathway; that means that the reaction is a one-step mechanism.

It is clear from the above example that there are three pi-bonds from diene and dienophile to produce two new sigma bonds and one pi-bond in the products.

The given reaction condition is drawn below.

The product during the Diels–Alder reaction is written below in a reaction:

Ans:

Double-barbed curve mechanism of the Diels–Alder reaction is