Carboxylic acid reacts with a base and forms a carboxylate ion and a water molecule. The base removes a proton from the carboxylic acid and forms a carboxylate ion.
Amines react with an acid (HCl) to form protonated amine and halide ion. The lone pair on nitrogen abstracts the proton (hydrogen) from HCl and forms the corresponding products.
The base abstracts the proton from an acid and forms a new bond to the proton of the acid. The acid (HA) loses proton and forms an electron pair on A.
The loss of proton from an acid gives a conjugate base and gain of proton by the base gives a conjugate acid.
The proton is nothing but the hydrogen atom. In the mechanism, the curved arrow shows the movement of the electron pair. Curved arrow is represented as:
The tail of the arrow begins at an electron pair and the head represents that moving of electron pair.
The reaction is as follows:
The reaction is as follows:
Ans:The curved arrow representation for the given reaction is as follows:
Thus, the curved arrow representation for the given reaction is as follows:
Add curved arrows to the reactants in this reaction. A double-barbed curved arrow is used to...
Add curved arrows to the reactants in this reaction. A double-barbed curved arrow is used to represent the movement of a pair of electrons.
Add curved arrows to the reactants in this reaction.A double barred curved arrow is used to represent the movement of a pair of electrons.
Add curved arrows to the reactants to show the formation of new bonds and the breaking of old bonds for the following Diels–Alder reaction. A double-barbed curved arrow is used to represent the movement of a pair of electrons. Ignore lone pairs or non-bonding electrons.
Add curved arrows to the reactants to show the formation of new bonds and the breaking of old bonds for the following Diels-Alder reaction. A double-barbed curved arrow is used to represent the movement of a pair of electrons. Ignore lone pairs or non-bonding electrons.
Add curved arrows to the reactants to show the formation of new bonds and the breaking of old bonds for the following Diels-Alder reaction. A double-barbed curve is used to represent the movement of a pair of electrons. The two solid wedges are suppose to be H's not methyl groups. Add curved arrows to the reactants to show the formation of new bonds and the breaking of old bonds for the following Diels-Alder reaction. A double-barbed curve is used to...
Add curved arrows to the reactants in this reaction.A double barred curved arrow is used to represent the movement of a pair of electrons.
Add curved arrows to the reactants to indicate the movement of electrons in this reaction. A double-headed curved arrow represents the movement of an electron pair.
Add one or more curved arrows to show the movement of electrons in the following reaction: Use the "curved arrow" button to add curved arrows. If needed, click on a drawn curved arrow to change it from double-to single-barbed.
Add one or more curved arrows to show the movement of electrons in the following reaction: Use the "curved arrow" button to add curved arrows. If needed, click on a drawn curved arrow to change it from double-to single-barbed. Học –––CH = HBC-8 + g–CHI
Add one or more curved arrows to show the movement of electrons in the following reaction Use the "curved arrow" button to add curved arrows. If needed, click on a drawn curved arrow to change it from double-to single-barbed. heat Học 6 8 CH, 1 "s Hạc + 6 –CH,